A cone of base radius $R$ and height $h$ is located in a uniform electric field $\vec E$ parallel to its base. The electric flux entering the cone is
$\frac{1}{2}\,EhR$
$E h R$
$2\, E h R$
$4\, E h R$
If $\oint_s \vec{E} \cdot \overrightarrow{d S}=0$ over a surface, then:
Electric field in a region is uniform and is given by $\vec{E}=a \hat{i}+b \hat{j}+c \hat{k}$. Electric flux associated with a surface of area $\vec{A}=\pi R^2 \hat{i}$ is
An uncharged sphere of metal is placed in between two charged plates as shown. The lines of force look like
The electric field in a region is given by $\vec E = \frac{3}{5}{E_0}\hat i + \frac{4}{5}{E_0}\hat j$ and $E_0 = 2\times10^3\, N/C$. Then, the flux of this field through a rectangular surface of area $0.2\, m^2$ parallel to the $y-z$ plane is......$\frac{{N - {m^2}}}{C}$
What can be said for electric charge if electric flux assocaited with closed loop is zero ?