A cone of base radius R and height h is locat | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) The electric flux $\phi$ through a surface is given by the projection of the area vector onto the electric field direction,or $\phi = \vec{E} \cdo

Vedclass · Accepted Answer

$EhR$

Vedclass · Answer

(B) The electric flux $\phi$ through a surface is given by the projection of the area vector onto the electric field direction,or $\phi = \vec{E} \cdot \vec{A}$.For a cone placed in a uniform electric field $\vec{E}$ parallel to its base,the flux entering the cone is equal to the flux passing through the projection of the cone onto a plane perpendicular to the electric field.The projection of the cone onto a plane perpendicular to the electric field is a triangle with base $2R$ and height $h$.The area of this triangular projection is $A = \frac{1}{2} 	imes 	ext{base} 	imes 	ext{height} = \frac{1}{2} 	imes (2R) 	imes h = Rh$.Since the electric field lines enter the cone through this projected area,the electric flux entering the cone is $\phi = E 	imes A = E 	imes (Rh) = EhR$.

$A$ cone of base radius $R$ and height $h$ is located in a uniform electric field $\vec{E}$ parallel to its base. The electric flux entering the cone is

Similar Questions

$A$ point charge $q$ is placed at a distance $a/2$ directly above the center of a square of side $a$. The electric flux through the square is:

$A$ charge $q$ is placed at one corner of a cube as shown in the figure. The flux of the electrostatic field $\overrightarrow{E}$ through the shaded area is ...... .

Gauss's law is true only if the force due to a charge varies as:

Three positive charges of equal value $q$ are placed at the vertices of an equilateral triangle. The resulting lines of force should be sketched as in:

Assertion : Electric lines of force never cross each other.
Reason : Electric field at a point superimpose to give one resultant electric field.

Vedclass Test Series

Exam Paper Generator

Online Exam Module