A charged particle is moving with velocity $v$ in a magnetic field of induction $B$. The force on the particle will be maximum when
$v$ and $B$ are in the same direction
$v$ and $B$ are in opposite directions
$v$ and $B$ are perpendicular
$v$ and $B$ are at an angle of $45^\circ $
If an electron enters a magnetic field with its velocity pointing in the same direction as the magnetic field, then
A current carrying long solenoid is placed on the ground with its axis vertical. A proton is falling along the axis of the solenoid with a velocity $v$. When the proton enters into the solenoid, it will
A magnetic field $\overrightarrow{\mathrm{B}}=\mathrm{B}_0 \hat{\mathrm{j}}$ exists in the region $\mathrm{a} < \mathrm{x} < 2 \mathrm{a}$ and $\vec{B}=-B_0 \hat{j}$, in the region $2 \mathrm{a} < \mathrm{x} < 3 \mathrm{a}$, where $\mathrm{B}_0$ is a positive constant. $\mathrm{A}$ positive point charge moving with a velocity $\overrightarrow{\mathrm{v}}=\mathrm{v}_0 \hat{\dot{i}}$, where $v_0$ is a positive constant, enters the magnetic field at $x=a$. The trajectory of the charge in this region can be like,
Show that a force that does no work must be a velocity dependent force.
An electron, moving in a uniform magnetic field of induction of intensity $\vec B,$ has its radius directly proportional to