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(D) According to Gauss's Law,the total electric flux $\varphi_{net}$ through a closed surface is equal to the total charge enclosed divided by the per

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$\frac{Q}{6 \varepsilon_{0}} 	imes 10^{-6}$

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(D) According to Gauss's Law,the total electric flux $\varphi_{net}$ through a closed surface is equal to the total charge enclosed divided by the permittivity of free space $\varepsilon_{0}$.For a cube with a charge $Q \; \mu C$ placed at its centre,the total flux is $\varphi_{net} = \frac{Q 	imes 10^{-6}}{\varepsilon_{0}}$.Since a cube has $6$ identical faces and the charge is at the centre,the flux is distributed equally among all faces.Therefore,the flux through any one face is $\varphi_{face} = \frac{\varphi_{net}}{6} = \frac{Q 	imes 10^{-6}}{6 \varepsilon_{0}} = \frac{Q}{6 \varepsilon_{0}} 	imes 10^{-6}$.

$A$ charge $Q \; \mu C$ is placed at the centre of a cube. The flux coming out from any one of its faces will be:

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