A charge Q is situated at the corner of a cub | vedclass

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Question

(C) According to Gauss's Law,the total electric flux through a closed surface is $\frac{1}{\varepsilon_0}$ times the net charge enclosed by the surfac

Vedclass · Accepted Answer

$\frac{Q}{8\varepsilon_0}$

Vedclass · Answer

(C) According to Gauss's Law,the total electric flux through a closed surface is $\frac{1}{\varepsilon_0}$ times the net charge enclosed by the surface.When a charge $Q$ is placed at the corner of a cube,it is shared by $8$ such identical cubes to form a larger symmetric closed surface (a Gaussian surface).Therefore,the total flux through the entire Gaussian surface is $\frac{Q}{\varepsilon_0}$.Since the charge is symmetrically distributed among $8$ cubes,the flux passing through one cube is $\frac{1}{8}$ of the total flux.Thus,the electric flux through the cube is $\Phi = \frac{Q}{8\varepsilon_0}$.

$A$ charge $Q$ is situated at the corner of a cube. The electric flux passing through all the six faces of the cube is:

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