What will be the total flux through the faces of the cube as shown in the figure with side of length $a$ if a charge $q$ is placed at:
$(a)$ $C$: centre of a face of the cube.
$(b)$ $D$: midpoint of $B$ and $C$.

Vedclass pdf generator app on play store
Vedclass iOS app on app store
(N/A) If the charge $q$ is placed at $C$,the centre of a face of the cube,the flux is shared equally by $2$ adjacent cubes.
Therefore,the flux through each cube is:
$\phi = \frac{q}{2\epsilon_{0}}$
$(b)$ If the charge $q$ is placed at $D$,the midpoint of the edge $BC$,the charge is shared by $4$ adjacent cubes.
Therefore,the flux through each cube is:
$\phi = \frac{q}{4\epsilon_{0}}$

Explore More

Similar Questions

$A$ cubical Gaussian surface has a side of length $a = 10 \,cm$. Electric field lines are parallel to the $X$-axis as shown in the figure. The magnitudes of the electric fields through surfaces $ABCD$ and $EFGH$ are $6 \,kNC^{-1}$ and $9 \,kNC^{-1}$ respectively. Then,the total charge enclosed by the cube is (Take $\varepsilon_0 = 9 \times 10^{-12} \,Fm^{-1}$): (in $\,nC$)

Which among the following has dimensions of charge?

Five charges $+q, +5q, -2q, +3q$ and $-4q$ are situated as shown in the figure. The electric flux due to this configuration through the surface $S$ is

$A$ hemisphere of radius $R$ is placed in a uniform electric field $E$ so that its axis is parallel to the field. Which of the following statement$(s)$ is/are true?

What kind of Gaussian surface is used to calculate the electric field due to the charge distribution?

Vedclass Products

For Students

Vedclass Test Series

Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.

Start Free Trial
For Teachers

Exam Paper Generator

Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.

Try Free
For Institutes

Online Exam Module

Live online exams with unlimited students, 360° analytics & white-label branding.

See Demo