$A$ capillary tube of radius $r$ is immersed in a liquid and the mass of the liquid which rises up in it is $M$. If the radius of the tube is doubled,then the mass of the liquid which will rise in the capillary tube will be ............

  • A
    $2 M$
  • B
    $M$
  • C
    $M / 2$
  • D
    $M / 4$

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Water rises to a height of $2 \,cm$ in a capillary tube. If the cross-sectional area of the tube is reduced to $\frac{1}{16}^{\text{th}}$ of the initial area, then water will rise to a height of: (in $\,cm$)

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