Water rises to a height of $2 \,cm$ in a capillary tube. If the cross-sectional area of the tube is reduced to $\frac{1}{16}^{\text{th}}$ of the initial area, then water will rise to a height of: (in $\,cm$)

Water rises to a height of $20 \,mm$ in a capillary tube of cross-sectional area $A$. If the area of cross-section of the tube is made $\frac{A}{4}$, then water will rise to a height of (in $\,cm$)

Two vertical parallel plates are partially submerged in water. The distance between the plates is equal to $d$. Water rises due to surface tension $T$,the width of the plates is $l$,and the contact angle of water with glass is $0^o$. Find the force of attraction between the plates.

Three liquids have the same surface tension and densities $\rho_1, \rho_2$,and $\rho_3$ $(\rho_1 > \rho_2 > \rho_3)$. In three identical capillaries,the rise of the liquid is the same. The corresponding angles of contact $\theta_1, \theta_2$,and $\theta_3$ are related as:

Water rises to a height of $16.3 \,cm$ in a capillary tube. If the tube is cut at a height of $12 \,cm$ above the water level,what will happen?

Water rises in a capillary tube to a height such that the upward force of surface tension balances the downward force of $75 \times 10^{-4} \ N$ due to the weight of the water. If the surface tension of water is $12 \times 10^{-2} \ N/m$,the internal circumference of the capillary must be: