Kerosene oil rises up the wick in a lantern due to:

$A$ $U$-tube with limbs of diameters $5\, mm$ and $2\, mm$ contains water of surface tension $7 \times 10^{-2} \, N/m$. The angle of contact is zero and the density of water is $10^3 \, kg/m^3$. If $g = 10 \, m/s^2$,then the difference in the liquid levels of the two limbs is:

In a capillary rise experiment,the water level rises to a height of $5\, cm$. If the same capillary tube is placed in water such that only $3\, cm$ of the tube projects outside the water level,then

The heat evolved for the rise of water when one end of the capillary tube of radius $r$ is immersed vertically into water is (Assume surface tension $= T$ and density of water to be $\rho$)

The water rises in the capillary to a height of $10\, cm$. If the surface tension of water is $73 \times 10^{-3}\, N/m$,density is $10^3\, kg/m^3$ and $g = 9.8\, m/s^2$,then find the radius of the capillary. (in $, cm$)

Water rises to a height of $16.3 \,cm$ in a capillary tube. If the tube is cut at a height of $12 \,cm$ above the water level,what will happen?