A body weight 500 ,N on the surface of the ea | vedclass

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Question

(b) Weight on surface of earth, $mg = 500\,N$ and weight below the surface of earth at $d = \frac{R}{2}$ 

$mg' = mg\left( {1 - \frac{d}{R}

Vedclass · Accepted Answer

$250$

Vedclass · Answer

(b) Weight on surface of earth, $mg = 500\,N$ and weight below the surface of earth at $d = \frac{R}{2}$ 

$mg' = mg\left( {1 - \frac{d}{R}} \right) = mg\left( {1 - \frac{1}{2}} \right) = \frac{{mg}}{2} = 250\,N$

A body weight $500 \,N$ on the surface of the earth. How much would it weigh half way below the surface of the earth ....... $N$

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