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Question

Using work - energy theorem

$W _{	ext {net }}=\left( K _{ f }- K _{ i }ight)$

$\Rightarrow-\frac{1}{2} Kx ^{2}=\frac{1}{2} m \left(\frac{ v }

Vedclass · Accepted Answer

$24$

Vedclass · Answer

Using work - energy theorem

$W _{	ext {net }}=\left( K _{ f }- K _{ i }ight)$

$\Rightarrow-\frac{1}{2} Kx ^{2}=\frac{1}{2} m \left(\frac{ v }{2}ight)^{2}-\frac{1}{2} mv ^{2}=\frac{ E }{4}- E$

$\Rightarrow \frac{1}{2} Kx ^{2}=\frac{3 E }{4} \Rightarrow K =\frac{3 E }{2 x ^{2}}$

$\Rightarrow K =\frac{3 E }{2 	imes\left(\frac{1}{4}ight)^{2}}=24\,E$

$n =24$

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