A uniform cable of mass $‘M’$ and length $‘L’$ is placed on a horizontal surface such that its ${\left( {\frac{1}{n}} \right)^{th}}$ part is hanging below the edge of the surface. To lift the hanging part of the cable upto the surface, the work done should be
A uniform cable of mass $‘M’$ and length $‘L’$ is placed on a horizontal surface such that its ${\left( {\frac{1}{n}} \right)^{th}}$ part is hanging below the edge of the surface. To lift the hanging part of the cable upto the surface, the work done should be
- [JEE MAIN 2019]
- A
$nMgL$
- B
$\frac {MgL}{2n^2}$
- C
$\frac {2MgL}{n^2}$
- D
$\frac {MgL}{n^2}$
Similar Questions
Velocity-time graph for a body of mass $10\, kg$ is shown in figure. Work-done on the body in first two seconds of the motion is ................ $\mathrm{J}$
Velocity-time graph for a body of mass $10\, kg$ is shown in figure. Work-done on the body in first two seconds of the motion is ................ $\mathrm{J}$
- [JEE MAIN 2016]
A particle of mass $2 \,kg$ travels along a straight line with velocity $v=a \sqrt{x}$, where $a$ is a constant. The work done by net force during the displacement of particle from $x=0$ to $x=4 \,m$ is .........
A particle of mass $2 \,kg$ travels along a straight line with velocity $v=a \sqrt{x}$, where $a$ is a constant. The work done by net force during the displacement of particle from $x=0$ to $x=4 \,m$ is .........
A uniform chain has a mass $m$ and length $l$. It is held on a frictionless table with one-sixth of its length hanging over the edge. The work done in just pulling the hanging part back on the table is
A uniform chain has a mass $m$ and length $l$. It is held on a frictionless table with one-sixth of its length hanging over the edge. The work done in just pulling the hanging part back on the table is
A body of mass $1\, kg$ is under a force, which causes a displacement in it is given by $x = \frac{{{t^3}}}{3}$ (in $m$). Find the work done by the force in first second ............ $\mathrm{J}$
A body of mass $1\, kg$ is under a force, which causes a displacement in it is given by $x = \frac{{{t^3}}}{3}$ (in $m$). Find the work done by the force in first second ............ $\mathrm{J}$
The bob of a pendulum is released from a horizontal position. If the length of the pendulum is $1.\;5 m$, what is the speed (in $m/s$) with which the bob arrives at the lowermost point, given that it dissipated $5\%$ of its initial energy against air resistance ?
The bob of a pendulum is released from a horizontal position. If the length of the pendulum is $1.\;5 m$, what is the speed (in $m/s$) with which the bob arrives at the lowermost point, given that it dissipated $5\%$ of its initial energy against air resistance ?