A barometer kept in an elevator accelerating upwards with acceleration $\mathrm{a}$. Find most likely pressure inside the elevator.
The resultant acceleration of elevator in upwards direction $=a+g$ $\therefore$ The pressure in elevator
$=h \rho(g+a)$
$=\frac{76 \times 13.6 \times(g+a)}{13.6 \times g} \mathrm{~cm} \mathrm{Hg}$
This pressure is greater than the atmospheric pressure $76 \mathrm{~cm} \mathrm{Hg}$.
A manometer reads the pressure of a gas in an enclosure as shown in Figure $(a)$ When a pump removes some of the gas, the manometer reads as in Figure $(b)$ The liquid used in the manometers is mercury and the atmospheric pressure is 76 cm of mercury.
$(a)$ Give the absolute and gauge pressure of the gas in the enclosure for cases $(a)$ and $(b)$, in units of cm of mercury.
$(b)$ How would the levels change in case $(b)$ if $13.6\; cm$ of water (immiscible with mercury) are poured into the right limb of the manometer ? (Ignore the small change in the volume of the gas).
A barometer kept in a stationary elevator reads $76 cm$. If the elevator starts accelerating up the reading will be
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A liquid $X$ of density $3.36\ g/cm^3$ is poured in a $U-$ tube, which contains $Hg$. Another liquid $Y$ is poured in left arm with height $8\ cm$, upper levels of $X$ and $Y$ are same. What is density of $Y$ .......... $g/cc$
Two identical cylindrical vessels with their bases at same level, each contains a liquid of density $d$ . The height of the liquid in one vessel is $ h_1$ and that in the other vessel is $h_2$ . The area of either base is $A$ . The work done by gravity in equalizing the levels when the two vessels are connected is