A liquid X of density 3.36 g/cm^3 is poured | vedclass

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(A) As shown in the figure, in the two arms of a tube, the pressure remains the same at the horizontal surface $PP'$.The pressure at level $PP'$ in th

Vedclass · Accepted Answer

$0.8$

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(A) As shown in the figure, in the two arms of a tube, the pressure remains the same at the horizontal surface $PP'$.The pressure at level $PP'$ in the left arm is due to the liquid $Y$ (height $8 \ cm$) and the mercury column (height $2 \ cm$).The pressure at level $PP'$ in the right arm is due to the liquid $X$ (height $10 \ cm$).Equating the pressures:$P_{left} = P_{right}$$h_Y ho_Y g + h_{Hg} ho_{Hg} g = h_X ho_X g$$8 	imes ho_Y + 2 	imes 13.6 = 10 	imes 3.36$$8 ho_Y + 27.2 = 33.6$$8 ho_Y = 33.6 - 27.2$$8 ho_Y = 6.4$$ho_Y = \frac{6.4}{8} = 0.8 \ g/cc$

$A$ liquid $X$ of density $3.36 \ g/cm^3$ is poured into a $U$-tube, which contains $Hg$. Another liquid $Y$ is poured into the left arm with a height of $8 \ cm$. The upper levels of $X$ and $Y$ are at the same height. What is the density of $Y$ in $g/cc$?

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