A bag contains $9$ discs of which $4$ are red, $3$ are blue and $2$ are yellow. The discs are similar in shape and size. A disc is drawn at random from the bag. Calculate the probability that it will be not blue,

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There are $9$ discs in all so the total number of possible outcomes is $9 .$

Let the events $A, \,B, \,C$ be defined as

$A:$ 'the disc drawn is red'

$B:$ 'the disc drawn is yellow'

$C:$ 'the disc drawn is blue'.

Clearly the event 'not blue' is 'not $C'$ .

We know that $P $ (not  $C$ ) $=1- P ( C )$

Therefore $P$ (not  $C$ ) $=1-\frac{1}{3}=\frac{2}{3}$

Similar Questions

An experiment involves rolling a pair of dice and recording the numbers that come up. Describe the following events:

$A:$ the sum is greater than $8$,

$B : 2$ occurs on either die

$C:$ the sum is at least $ 7$ and a multiple of $3.$

Which pairs of these events are mutually exclusive ?

Describe the sample space for the indicated experiment: A coin is tossed and then a die is rolled only in case a head is shown on the coin.

If $A$ is a sure event, then the value of $P (A$ not ) is

Let $\Omega$ be the sample space and $A \subseteq \Omega$ be an event. Given below are two statements :

$(S1)$ : If $P ( A )=0$, then $A =\phi$

$( S 2)$ : If $P ( A )=$, then $A =\Omega$

Then

  • [JEE MAIN 2023]

‘$A$’ draws two cards with replacement from a pack of $52$ cards and ‘$B$' throws a pair of dice what is the chance that ‘$A$’ gets both cards of same suit and ‘$B$’ gets total of $6$