‘A’ draws two cards with replacem | vedclass

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Question

(c) The probaility of drawing two cards of same suit

$ = \frac{{13}}{{52}} 	imes \frac{{13}}{{52}}$ and it can be of any suit out of $4$.

So $P

Vedclass · Accepted Answer

$\frac{5}{{144}}$

Vedclass · Answer

(c) The probaility of drawing two cards of same suit

$ = \frac{{13}}{{52}} 	imes \frac{{13}}{{52}}$ and it can be of any suit out of $4$.

So $P(A) = \frac{{4 	imes 13 	imes 13}}{{52 	imes 52}} = \frac{1}{4}$ and

$P(B) = \frac{5}{{36}}$

Thus $P(A \cap B) = P(A)\,.\,P(B) = \frac{1}{4} 	imes \frac{5}{{36}} = \frac{5}{{144}}.$

‘$A$’ draws two cards with replacement from a pack of $52$ cards and ‘$B$' throws a pair of dice what is the chance that ‘$A$’ gets both cards of same suit and ‘$B$’ gets total of $6$

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