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(B) The pressure $P$ at the bottom of the container due to a liquid column of height $h$ is given by $P = h \rho g$.The force $F$ exerted on the botto

Vedclass · Accepted Answer

$7.2$

Vedclass · Answer

(B) The pressure $P$ at the bottom of the container due to a liquid column of height $h$ is given by $P = h ho g$.The force $F$ exerted on the bottom area $A$ is given by $F = P 	imes A$.Substituting the values: $h = 0.4 \ m$,$ho = 900 \ kg/m^{3}$,$g = 10 \ m/s^{2}$,and $A = 2 	imes 10^{-3} \ m^{2}$.$F = (h ho g) 	imes A$$F = 0.4 	imes 900 	imes 10 	imes (2 	imes 10^{-3})$$F = 3600 	imes 2 	imes 10^{-3}$$F = 7200 	imes 10^{-3} = 7.2 \ N$.

The density of the liquid filled in the container is $900 \ kg/m^{3}$. Calculate the force exerted on the bottom of the container. (Given: $g = 10 \ m/s^{2}$) (in $N$)

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