Easy
In how many ways can two balls of the same color be selected from $4$ distinct black balls and $3$ distinct white balls?
- A$5$
- B$6$
- C$9$
- D$8$
Explore More
Similar Questions
If $^{43}C_{r-6} = ^{43}C_{3r+1}$,then the value of $r$ is
Easy
View SolutionOut of $10$ white,$9$ black and $7$ red balls,the number of ways in which selection of one or more balls can be made,is
Medium
View SolutionThe value of ${ }^{49} C_3+{ }^{48} C_3+{ }^{47} C_3+{ }^{46} C_3+{ }^{45} C_3+{ }^{45} C_4$ is
If the total number of $m$-element subsets of the set $A = \{a_{1}, a_{2}, \ldots, a_{n}\}$ is $k$ times the number of $m$-element subsets containing $a_{4}$,then $n$ is
MediumWBJEE 2020
View SolutionIf $^nC_{12} = ^nC_6$,then $^nC_2 = $
Easy
View SolutionVedclass Products
For Students
Vedclass Test Series
Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.
Start Free TrialFor Teachers
Exam Paper Generator
Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.
Try FreeFor Institutes
Online Exam Module
Live online exams with unlimited students, 360° analytics & white-label branding.
See Demo