If $n = 1000!$,then $\frac{1}{\log_2 n} + \frac{1}{\log_3 n} + ... + \frac{1}{\log_{1000} n} = ......$
- A$0$
- B$1$
- C$10$
- D$1000$
Explore More
Similar Questions
The value of $(0.16)^{\log _{2.5}\left(\frac{1}{3}+\frac{1}{3^{2}}+\frac{1}{3^{3}}+\ldots \infty\right)}$ is equal to
DifficultJEE MAIN 2020
View SolutionIf $y = 2^{1/\log_x 4}$,then $x$ is equal to
Medium
View SolutionIf $3^x = 4^{x-1}$,then $x = $
MediumIIT 2013
View SolutionWhat is the number of solutions for the equation $\log_4(x - 1) = \log_2(x - 3)$?
Difficult
View Solution$7 \log \left( \frac{16}{15} \right) + 5 \log \left( \frac{25}{24} \right) + 3 \log \left( \frac{81}{80} \right)$ is equal to
Easy
View SolutionVedclass Products
For Students
Vedclass Test Series
Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.
Start Free TrialFor Teachers
Exam Paper Generator
Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.
Try FreeFor Institutes
Online Exam Module
Live online exams with unlimited students, 360° analytics & white-label branding.
See Demo