For a given medium,the polarizing angle is 60 | vedclass

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(D) The relationship between the refractive index $\mu$,the polarizing angle $i_p$,and the critical angle $i_c$ is given by:$\mu = 	an i_p$ and $\mu

Vedclass · Accepted Answer

$\sin^{-1} \frac{1}{\sqrt{3}}$

Vedclass · Answer

(D) The relationship between the refractive index $\mu$,the polarizing angle $i_p$,and the critical angle $i_c$ is given by:$\mu = 	an i_p$ and $\mu = \frac{1}{\sin i_c}$.Equating these,we get $	an i_p = \frac{1}{\sin i_c}$.Given $i_p = 60^{\circ}$,we have $	an 60^{\circ} = \frac{1}{\sin i_c}$.Since $	an 60^{\circ} = \sqrt{3}$,it follows that $\sqrt{3} = \frac{1}{\sin i_c}$.Therefore,$\sin i_c = \frac{1}{\sqrt{3}}$,which implies $i_c = \sin^{-1} \left( \frac{1}{\sqrt{3}} ight)$.

For a given medium,the polarizing angle is $60^{\circ}$. The critical angle for this medium is . . . . . .

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