Light is incident at an angle i on a glass sl | vedclass

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(A) According to Brewster's law,when unpolarised light is incident on a transparent medium at the polarising angle $i$,the reflected ray is completely

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$90^{\circ}-i$

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(A) According to Brewster's law,when unpolarised light is incident on a transparent medium at the polarising angle $i$,the reflected ray is completely plane-polarised.In this condition,the reflected ray and the refracted ray are perpendicular to each other,meaning the angle between them is $90^{\circ}$.From the geometry of the reflection and refraction at the interface,the sum of the angle of incidence $i$,the angle between the reflected and refracted rays $(90^{\circ})$,and the angle of refraction $r$ must equal $180^{\circ}$ (as they form a straight line along the interface).Therefore,$i + 90^{\circ} + r = 180^{\circ}$.Solving for $r$,we get $r = 180^{\circ} - 90^{\circ} - i = 90^{\circ} - i$.

Light is incident at an angle $i$ on a glass slab. The reflected ray is completely polarised. The angle of refraction is

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