$A$ transparent medium shows a relationship between $\sin i$ and $\sin r$ as shown in the graph. If the speed of light in vacuum is $c$,the Brewster angle for the medium is: (in $^{\circ}$)

  • A
    $60$
  • B
    $30$
  • C
    $90$
  • D
    $45$

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Unpolarised light is incident on the boundary between two dielectric media,whose dielectric constants are $2.8$ (medium $1$) and $6.8$ (medium $2$),respectively. To satisfy the condition that the reflected and refracted rays are perpendicular to each other,the angle of incidence should be $\tan ^{-1}\left(1+\frac{10}{\theta}\right)^{\frac{1}{2}}$. The value of $\theta$ is $.............$ (Given for dielectric media,$\mu_{r}=1$)

An unpolarised light beam strikes a glass surface at Brewster's angle. Then

The polarising angle of a transparent medium is $\theta$. Let the speed of light in the medium be $v$. Then the relation between $\theta$ and $v$ is [where $c$ is the velocity of light in air].

Explain the polarisation of light by reflection,state Brewster's law,and derive its formula.

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The refractive index of a medium is equal to the tangent of the polarizing angle. This is known as:

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