$A$ monoatomic gas is supplied heat $Q$ very slowly while keeping the pressure constant. The work done by the gas will be

$10 \text{ mole}$ of an ideal gas is undergoing the process shown in the figure. The heat involved in the process from $P_1$ to $P_2$ at constant volume $V = 1 \text{ m}^3$ is $\alpha \text{ Joule}$ ($P_1 = 21.7 \text{ Pa}$,$P_2 = 30 \text{ Pa}$,$C_v = 21 \text{ J/K} \cdot \text{mol}$,$R = 8.3 \text{ J/mol} \cdot \text{K}$). The value of $\alpha$ is . . . . . . .

Which one of the following equations specifies an isobaric process?
$[Q=$ heat supplied; $\Delta P, \Delta V$ and $\Delta T$ are change in pressure,volume,and temperature respectively.]

If $R$ is the universal gas constant,the amount of heat needed to raise the temperature of $2$ moles of an ideal monoatomic gas from $273 \ K$ to $373 \ K$ when no work is done is: (in $R$)

In an isobaric process,the work done by a diatomic gas is $10 \ J$. The heat given to the gas will be (in $J$):

$A$ diatomic ideal gas undergoes a thermodynamic change according to the $P-V$ diagram shown in the figure. The heat given to the gas in process $AB$ is: (in $, P_0 V_0$)