10 text{ mole} of an ideal gas is undergoing | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) The process from $P_1$ to $P_2$ occurs at a constant volume $V = 1 	ext{ m}^3$.For an isochoric process,the heat exchanged is given by $\Delta Q

Vedclass · Accepted Answer

$21$

Vedclass · Answer

(C) The process from $P_1$ to $P_2$ occurs at a constant volume $V = 1 	ext{ m}^3$.For an isochoric process,the heat exchanged is given by $\Delta Q = n C_v \Delta T$.Using the ideal gas law $PV = nRT$,we have $nR \Delta T = V \Delta P$.Substituting this into the heat equation: $\Delta Q = \frac{C_v}{R} (nR \Delta T) = \frac{C_v}{R} V (P_2 - P_1)$.Given $n = 10 	ext{ mol}$,$C_v = 21 	ext{ J/K} \cdot 	ext{mol}$,$R = 8.3 	ext{ J/mol} \cdot 	ext{K}$,$V = 1 	ext{ m}^3$,$P_1 = 21.7 	ext{ Pa}$,and $P_2 = 30 	ext{ Pa}$.$\Delta Q = \frac{21}{8.3} 	imes 1 	imes (30 - 21.7) = \frac{21}{8.3} 	imes 8.3 = 21 	ext{ J}$.Thus,$\alpha = 21$.

Similar Questions

$A$ diatomic gas,having $C_{p} = \frac{7}{2} R$ and $C_{v} = \frac{5}{2} R$,is heated at constant pressure. The ratio $dU : dQ : dW$ is:

$A$ certain amount of heat energy is supplied to a monoatomic ideal gas which expands at constant pressure. What fraction of the heat energy is converted into work?

$A$ diatomic gas with rigid molecules does $10 \ J$ of work when expanded at constant pressure. What would be the heat energy absorbed by the gas,in this process ..... $J$.

$A$ quantity of heat $Q$ is supplied to a monoatomic ideal gas which expands at constant pressure. The fraction of heat that goes into work done by the gas is

At constant pressure,what fraction of the heat supplied to an ideal gas is converted into mechanical work?

Vedclass Test Series

Exam Paper Generator

Online Exam Module