For the reaction $2NO_{(g)} + O_{2_{(g)}} \rightarrow 2NO_{2_{(g)}}$,the volume of the reaction vessel is suddenly reduced to half of its original volume. If the reaction is first order with respect to $O_2$ and second order with respect to $NO$,the rate of the reaction will:

  • A
    Increase $8$ times its initial value.
  • B
    Increase $4$ times its initial value.
  • C
    Become $1/4$ of its initial value.
  • D
    Become $1/8$ of its initial value.

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Similar Questions

Order of a reaction is decided by

$t_{1/2} =$ constant confirms the first order reaction. If $a^2 t_{1/2} =$ constant,it confirms that the order of reaction is ($a =$ initial concentration of reactant).

During the kinetic study of the reaction,$2A + B \rightarrow C + D,$ the following results were obtained:
$Run$ $[A] / mol \ L^{-1}$ $[B] / mol \ L^{-1}$ Initial rate of formation of $D / mol \ L^{-1} \ min^{-1}$
$I.$ $0.1$ $0.1$ $6.0 \times 10^{-3}$
$II.$ $0.3$ $0.2$ $7.2 \times 10^{-2}$
$III.$ $0.3$ $0.4$ $2.88 \times 10^{-1}$
$IV.$ $0.4$ $0.1$ $2.40 \times 10^{-2}$

Based on the above data,which one of the following is correct?

What is the molecularity and order of the following reaction if the rate law is $\text{rate} = k[O_3][O]$ respectively?
$O_{3(g)} + O_{(g)} \longrightarrow 2O_{2(g)}$

For the reaction $X_{2(g)} + Y_{2(g)} \rightarrow 2XY_{(g)}$,the following data are observed:
$[X_{2}] \ (M)$$[Y_{2}] \ (M)$Rate of appearance of $XY \ (M \ sec^{-1})$
$0.1$$0.1$$5 \times 10^{-6}$
$0.2$$0.1$$10^{-5}$
$0.2$$0.2$$4 \times 10^{-5}$

Calculate the rate constant of the reaction (in $M^{1-n} \ sec^{-1}$),where $n$ is the order of the reaction.

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