$\underset{n\to \infty }{\mathop{\lim }}\,\frac{{{1}^{99}}+{{2}^{99}}+{{3}^{99}}+......{{n}^{99}}}{{{n}^{100}}}=$

  • A
    $\frac{9}{100}$
  • B
    $\frac{1}{100}$
  • C
    $\frac{1}{99}$
  • D
    $\frac{1}{101}$

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