$50\, gm$ of ice at $0°C$ is mixed with $50\, gm$ of water at $80°C,$ final temperature of mixture will be........ $^oC$
$0$
$40$
$40$
$4$
When $x\, grams$ of steam at $100\,^oC$ is mixed with $y\,grams$ of ice at $0\,^oC$ , We obtain $(x + y)\,grams$ of water at $100\,^oC$ . What is the ratio $y/x$ ?
$10 \,gm$ of ice at $-20^{\circ} C$ is kept into a calorimeter containing $10 \,gm$ of water at $10^{\circ} C$. The specific heat of water is twice that of ice. When equilibrium is reached, the calorimeter will contain ..........
Three liquids with masses ${m_1},\,{m_2},\,{m_3}$ are thoroughly mixed. If their specific heats are ${c_1},\,{c_2},\,{c_3}$ and their temperatures ${T_1},\,{T_2},\,{T_3}$ respectively, then the temperature of the mixture is
$1\, g$ of a steam at $100°C$ melt ........ $gm$ ice at $0°C\,?$ $($Latent heat of ice $= 80 \,cal/gm$ and latent heat of steam $= 540\, cal/gm)$
Calculate the amount of heat (in calories) required to convert $5\,\, gm$ of ice at $0\,^oC$ to steam at $100\,^oC$