Calculate the amount of heat (in calories) re | vedclass

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(C) The total heat $Q$ required is the sum of heat for three processes: melting ice,heating water,and vaporizing water.$Q_1$ (melting ice at $0\,^{\ci

Vedclass · Accepted Answer

$3600$

Vedclass · Answer

(C) The total heat $Q$ required is the sum of heat for three processes: melting ice,heating water,and vaporizing water.$Q_1$ (melting ice at $0\,^{\circ}C$): $m 	imes L_f = 5\,g 	imes 80\,cal/g = 400\,cal$.$Q_2$ (heating water from $0\,^{\circ}C$ to $100\,^{\circ}C$): $m 	imes c 	imes \Delta T = 5\,g 	imes 1\,cal/g^{\circ}C 	imes 100\,^{\circ}C = 500\,cal$.$Q_3$ (vaporizing water at $100\,^{\circ}C$): $m 	imes L_v = 5\,g 	imes 540\,cal/g = 2700\,cal$.Total heat $Q = Q_1 + Q_2 + Q_3 = 400 + 500 + 2700 = 3600\,cal$.

Calculate the amount of heat (in calories) required to convert $5\,g$ of ice at $0\,^{\circ}C$ to steam at $100\,^{\circ}C$.

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