When $x\, grams$ of steam at $100\,^oC$ is mixed  with $y\,grams$ of ice at $0\,^oC$ , We obtain $(x + y)\,grams$ of water at $100\,^oC$  . What is the ratio $y/x$ ?

Two tanks $A$ and $B$ contain water at $30\,^oC$ and $80\,^oC$ respectively. Calculate the amount of water that must be taken from each tank to prepare $40\,kg$ water at $50\,^oC$

Calculate the amount of heat (in calories) required to convert $5\,\, gm$ of ice at $0\,^oC$ to steam at $100\,^oC$

$50\, g$ ice at $0\,^oC$ is dropped into a calorimeter containing $100\, g$ water at $30\,^oC$. If thermal capacity of calorimeter is zero then amount of ice left in the mixture at equilibrium is ........ $gm$

We have half a bucket ($6$ litre) of water at $20^oC $.If we want water at $40^oC$, how much steam at $100^oC$ should be added to it ?

In an industrial process $10\, kg$ of water per hour is to be heated from $20°C$ to $80°C$. To do this steam at $150°C$ is passed from a boiler into a copper coil immersed in water. The steam condenses in the coil and is returned to the boiler as water at $90°C.$ how many $kg$ of steam is required per hour. $($Specific heat of steam $= 1$ $calorie \,per\, gm°C,$ Latent heat of vaporisation $= 540 \,cal/gm)$