sin ^4 frac{pi}{8} + cos ^4 frac{3 pi}{8} - s | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(D) આપેલ પદાવલિ: $E = \sin ^4 \frac{\pi}{8} + \cos ^4 \frac{3 \pi}{8} - \sin ^4 \frac{3 \pi}{8} + \sin ^4 \frac{5 \pi}{8} + \cos ^4 \frac{7 \pi}{8} -

Vedclass · Accepted Answer

$\frac{3}{4}$

Vedclass · Answer

(D) આપેલ પદાવલિ: $E = \sin ^4 \frac{\pi}{8} + \cos ^4 \frac{3 \pi}{8} - \sin ^4 \frac{3 \pi}{8} + \sin ^4 \frac{5 \pi}{8} + \cos ^4 \frac{7 \pi}{8} - \sin ^4 \frac{7 \pi}{8}$ $\sin(\pi - 	heta) = \sin 	heta$ અને $\cos(\pi - 	heta) = -\cos 	heta$ નો ઉપયોગ કરતા: $\sin^4 \frac{5 \pi}{8} = \sin^4 \frac{3 \pi}{8}$ $\cos^4 \frac{7 \pi}{8} = \cos^4 \frac{\pi}{8}$ $\sin^4 \frac{7 \pi}{8} = \sin^4 \frac{\pi}{8}$ કિંમતો મૂકતા: $E = \cos ^4 \frac{3 \pi}{8} + \cos ^4 \frac{\pi}{8}$ $\cos^2 	heta = \frac{1 + \cos 2 	heta}{2}$ સૂત્રનો ઉપયોગ કરતા: $E = \frac{3}{4}$

$\sin ^4 \frac{\pi}{8} + \cos ^4 \frac{3 \pi}{8} - \sin ^4 \frac{3 \pi}{8} + \sin ^4 \frac{5 \pi}{8} + \cos ^4 \frac{7 \pi}{8} - \sin ^4 \frac{7 \pi}{8} = ?$

Similar Questions

પદાવલિ $[1 - \sin(3\pi - \alpha) + \cos(3\pi + \alpha)] [1 - \sin(\frac{3\pi}{2} - \alpha) + \cos(\frac{5\pi}{2} - \alpha)]$ નું સાદું રૂપ આપતા શું મળે?

જો $\tan \theta = -\frac{4}{3}$ હોય,તો $\sin \theta = $

જો $\sec \theta = \frac{13}{12}$ અને $\theta$ એ $4^{\text{th}}$ ચરણમાં હોય,તો $\tan \theta \times \operatorname{cosec} \theta \times \sin \theta \times \cos \theta = $

જો $\sin x = -\frac{3}{5}$,જ્યાં $\pi < x < \frac{3\pi}{2}$ હોય,તો $80(\tan^2 x - \cos x)$ ની કિંમત શોધો:

$\sin (\pi + \theta )\sin (\pi - \theta )\csc^2 \theta = $

Vedclass Test Series

Exam Paper Generator

Online Exam Module