(C) The expected value $E(X)$ of a discrete random variable $X$ is calculated using the formula $E(X) = \sum x_i P(x_i)$.Given values of $X$ are $10,

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

(C) The expected value $E(X)$ of a discrete random variable $X$ is calculated using the formula $E(X) = \sum x_i P(x_i)$.Given values of $X$ are $10, 20, 30, 40$ and their respective probabilities are $0.3, 0.3, 0.2, 0.2$.Substituting these values into the formula:$E(X) = (10 \times 0.3) + (20 \times 0.3) + (30 \times 0.2) + (40 \times 0.2)$$E(X) = 3 + 6 + 6 + 8$$E(X) = 23$Therefore,the expected value of $X$ is $23$.

Class 12 Mathematics Probability Probability distribution

Easy

$A$ discrete random variable $X$ takes values $10, 20, 30,$ and $40$,with probabilities $0.3, 0.3, 0.2,$ and $0.2$ respectively. Then the expected value of $X$ is

AP EAMCET 2021 All AP EAMCET

A
$12$
B
$22$
C
$23$
D
$24$

Explore More

Browse All

Question Bank

All Subjects

Class 12 Questions

Class 12

Mathematics Questions

Chapter

Probability

Subtopic

Probability distribution

Previous Year

AP EAMCET 2021 Paper All AP EAMCET years →

The range of a random variable $X$ is $\{0, 1, 2\}$. If $P(X = 0) = 3c^3$,$P(X = 1) = 4c - 10c^2$,and $P(X = 2) = 5c - 1$,then find $P(0 < X \le 2)$.

EasyTS EAMCET 2021

View Solution

The probability distribution of a random variable $X$ is given below:
$X = x$ $0$ $1$ $2$ $3$ $4$ $5$ $6$ $7$
$P(X = x)$ $0$ $k$ $2k$ $2k$ $3k$ $k^2$ $2k^2$ $7k^2 + k$

Then,$P(0 < X < 4)$ is equal to:

MediumTS EAMCET 2021

View Solution

Let $X$ denote the sum of the numbers obtained when two fair dice are rolled. Find the variance and standard deviation of $X$.

Difficult

View Solution

If $X$ is a random variable with cumulative distribution function $F(x)$ and its probability distribution is given by the following table:
$X = x$ $-1.5$ $-0.5$ $0.5$ $1.5$ $2.5$
$P(X = x)$ $0.05$ $0.2$ $0.15$ $0.25$ $0.35$

Then,find the value of $F(1.5) - F(-0.5)$.

$X = x$	$-1.5$	$-0.5$	$0.5$	$1.5$	$2.5$
$P(X = x)$	$0.05$	$0.2$	$0.15$	$0.25$	$0.35$

MediumMHT CET 2020

View Solution

$A$ random variable $X$ has the following probability distribution:
$X$ $0$ $1$ $2$ $3$ $4$ $5$ $6$
$P(X)$ $k$ $3k$ $5k$ $7k$ $9k$ $11k$ $13k$

Then find $P(X \ge 2)$.

$X$	$0$	$1$	$2$	$3$	$4$	$5$	$6$
$P(X)$	$k$	$3k$	$5k$	$7k$	$9k$	$11k$	$13k$

MediumMHT CET 2022

View Solution

Vedclass Products

For Students

Vedclass Test Series

Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.

Start Free Trial

For Teachers

Exam Paper Generator

Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.

Try Free

For Institutes

Online Exam Module

Live online exams with unlimited students, 360° analytics & white-label branding.

See Demo

$X = x$	$0$	$1$	$2$	$3$	$4$	$5$	$6$	$7$
$P(X = x)$	$0$	$k$	$2k$	$2k$	$3k$	$k^2$	$2k^2$	$7k^2 + k$

$A$ discrete random variable $X$ takes values $10, 20, 30,$ and $40$,with probabilities $0.3, 0.3, 0.2,$ and $0.2$ respectively. Then the expected value of $X$ is

Similar Questions

The range of a random variable $X$ is $\{0, 1, 2\}$. If $P(X = 0) = 3c^3$,$P(X = 1) = 4c - 10c^2$,and $P(X = 2) = 5c - 1$,then find $P(0 < X \le 2)$.

The probability distribution of a random variable $X$ is given below:$X = x$$0$$1$$2$$3$$4$$5$$6$$7$$P(X = x)$$0$$k$$2k$$2k$$3k$$k^2$$2k^2$$7k^2 + k$Then,$P(0 < X < 4)$ is equal to:

Let $X$ denote the sum of the numbers obtained when two fair dice are rolled. Find the variance and standard deviation of $X$.

If $X$ is a random variable with cumulative distribution function $F(x)$ and its probability distribution is given by the following table:$X = x$$-1.5$$-0.5$$0.5$$1.5$$2.5$$P(X = x)$$0.05$$0.2$$0.15$$0.25$$0.35$Then,find the value of $F(1.5) - F(-0.5)$.

$A$ random variable $X$ has the following probability distribution:$X$$0$$1$$2$$3$$4$$5$$6$$P(X)$$k$$3k$$5k$$7k$$9k$$11k$$13k$Then find $P(X \ge 2)$.

Vedclass Test Series

Exam Paper Generator

Online Exam Module

The probability distribution of a random variable $X$ is given below:
$X = x$ $0$ $1$ $2$ $3$ $4$ $5$ $6$ $7$
$P(X = x)$ $0$ $k$ $2k$ $2k$ $3k$ $k^2$ $2k^2$ $7k^2 + k$

Then,$P(0 < X < 4)$ is equal to:

If $X$ is a random variable with cumulative distribution function $F(x)$ and its probability distribution is given by the following table:
$X = x$ $-1.5$ $-0.5$ $0.5$ $1.5$ $2.5$
$P(X = x)$ $0.05$ $0.2$ $0.15$ $0.25$ $0.35$

Then,find the value of $F(1.5) - F(-0.5)$.

$A$ random variable $X$ has the following probability distribution:
$X$ $0$ $1$ $2$ $3$ $4$ $5$ $6$
$P(X)$ $k$ $3k$ $5k$ $7k$ $9k$ $11k$ $13k$

Then find $P(X \ge 2)$.