The probability distribution of a random variable $X$ is given below:
$X = x$ $0$ $1$ $2$ $3$ $4$ $5$ $6$ $7$ $P(X = x)$ $0$ $k$ $2k$ $2k$ $3k$ $k^2$ $2k^2$ $7k^2 + k$
Then,$P(0 < X < 4)$ is equal to:
| $X = x$ | $0$ | $1$ | $2$ | $3$ | $4$ | $5$ | $6$ | $7$ |
| $P(X = x)$ | $0$ | $k$ | $2k$ | $2k$ | $3k$ | $k^2$ | $2k^2$ | $7k^2 + k$ |
Then,$P(0 < X < 4)$ is equal to:
- A$\frac{4}{5}$
- B$\frac{3}{5}$
- C$\frac{1}{2}$
- D$\frac{1}{4}$
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DifficultTS EAMCET 2020
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