A uniform electric field exists in the plane | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(D) In a uniform electric field, the electric potential $V$ decreases in the direction of the electric field lines. The potential at any point $(x, y)

Vedclass · Accepted Answer

$V_{A}=V_{B}, V_{C} > V_{D}$

Vedclass · Answer

(D) In a uniform electric field, the electric potential $V$ decreases in the direction of the electric field lines. The potential at any point $(x, y)$ in a uniform electric field $\vec{E} = E\hat{i}$ is given by $V = -Ex + 	ext{constant}$.Points on the same vertical line (perpendicular to the field lines) have the same potential because they have the same $x$-coordinate.Looking at the diagram:$1$. Points $A$ and $B$ are at the same vertical position relative to the field lines, but they are not on the same vertical line. However, the question asks for the relationship between potentials. Let's analyze the $x$-coordinates.$2$. Point $C$ is at the leftmost position, so it has the smallest $x$-coordinate, meaning $V_{C}$ is the highest.$3$. Point $D$ is at the rightmost position, so it has the largest $x$-coordinate, meaning $V_{D}$ is the lowest.$4$. Points $A$ and $B$ have the same $x$-coordinate, so $V_{A} = V_{B}$.$5$. Since $C$ is to the left of $D$, $V_{C} > V_{D}$.Thus, the correct relationship is $V_{A} = V_{B}$ and $V_{C} > V_{D}$.

$A$ uniform electric field exists in the plane of the paper as shown. Here $A, B, C$, and $D$ are points on the circle. $V_{A}, V_{B}, V_{C}$, and $V_{D}$ are the potentials at those points respectively. Then:

Similar Questions

Draw an equipotential surface of two identical positive charges for small distance.

In an electric field due to charge $Q$,a charge $q$ moves from point $A$ to $B$ along an arc of a circle centered at $Q$,as shown in the figure. The work done is ($\varepsilon_0=$ permittivity of free space).

The points having equal potentials are:

$A$ circle of radius $R$ is drawn in a uniform electric field as shown in the figure. If the potentials at points $A, B, C,$ and $D$ on the circumference of the circle are $V_A, V_B, V_C,$ and $V_D$ respectively,then:

Vedclass Test Series

Exam Paper Generator

Online Exam Module