Draw an equipotential surface of two identical positive charges for small distance.
(N/A) When two identical positive charges are placed at a small distance from each other,they repel each other. The electric field lines originate from the positive charges and move outwards.
An equipotential surface is a surface where the electric potential is constant at all points.
For two identical positive charges,the equipotential surfaces are not spherical. Near each charge,the surfaces are nearly spherical,but as we move towards the region between the charges,the surfaces distort and merge.
In the region between the two charges,the electric field is weak (the neutral point exists at the midpoint),causing the equipotential surfaces to bulge outwards and eventually form a single surface enclosing both charges at larger distances.
An equipotential surface is a surface where the electric potential is constant at all points.
For two identical positive charges,the equipotential surfaces are not spherical. Near each charge,the surfaces are nearly spherical,but as we move towards the region between the charges,the surfaces distort and merge.
In the region between the two charges,the electric field is weak (the neutral point exists at the midpoint),causing the equipotential surfaces to bulge outwards and eventually form a single surface enclosing both charges at larger distances.
Explore More
Similar Questions
There is $10$ units of charge at the centre of a circle of radius $10\,m$. The work done in moving $1\,unit$ of charge around the circle once is...........$units$.
Two point charges of magnitude $+q$ and $-q$ are placed at $\left( -\frac{d}{2}, 0, 0 \right)$ and $\left( \frac{d}{2}, 0, 0 \right)$,respectively. Find the equation of the equipotential surface where the potential is zero.
Medium
View SolutionGiven below are two statements: one is labelled as Assertion $(A)$ and the other is labelled as Reason $(R)$.
Assertion $(A)$: Work done by an electric field on moving a positive charge on an equipotential surface is always zero.
Reason $(R)$: Electric lines of force are always perpendicular to equipotential surfaces.
In the light of the above statements,choose the most appropriate answer from the options given below:
Assertion $(A)$: Work done by an electric field on moving a positive charge on an equipotential surface is always zero.
Reason $(R)$: Electric lines of force are always perpendicular to equipotential surfaces.
In the light of the above statements,choose the most appropriate answer from the options given below:
DifficultJEE MAIN 2024
View SolutionWhat is the direction of the lines of force at any point on the equipotential surface?
$A$ uniform electric field of magnitude $E = 100 \ V/m$ is directed along the line $y = x + 3$. Find the potential difference $V_A - V_B$ between points $A(3, 1)$ and $B(1, 3)$.
Medium
View SolutionVedclass Products
For Students
Vedclass Test Series
Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.
Start Free TrialFor Teachers
Exam Paper Generator
Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.
Try FreeFor Institutes
Online Exam Module
Live online exams with unlimited students, 360° analytics & white-label branding.
See Demo