(D) For a long straight wire of radius $r$ carrying a uniform current $I$,the magnetic field $B$ at a distance $a$ from the axis inside the wire $(a <

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(D) For a long straight wire of radius $r$ carrying a uniform current $I$,the magnetic field $B$ at a distance $a$ from the axis inside the wire $(a Using Ampere's circuital law: $\oint B \cdot dl = \mu_0 I_{enclosed}$.For a point inside the wire,the enclosed current $I_{enclosed} = I \times (\frac{\pi a^2}{\pi r^2}) = I \frac{a^2}{r^2}$.Thus,$B(2 \pi a) = \mu_0 I \frac{a^2}{r^2}$.Solving for $B$,we get $B = \frac{\mu_0 I a}{2 \pi r^2}$.Since $\mu_0$,$I$,and $r$ are constants,$B \propto a$.

Class 12 Physics Moving Charges and Magnetism Ampere’s circuital law and its application (Solenoid and Toroid)

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$A$ very long straight wire of radius $r$ carries current $I$. The intensity of the magnetic field $B$ at a point,lying at a perpendicular distance $a$ from the axis is proportional to: (where $a < r$)

GUJCET 2018 All GUJCET

A
$a^2$
B
$1/a^2$
C
$1/a$
D
$a$

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Class 12

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Moving Charges and Magnetism

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Ampere’s circuital law and its application (Solenoid and Toroid)

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$A$ very long straight wire of radius $r$ carries current $I$. The intensity of the magnetic field $B$ at a point,lying at a perpendicular distance $a$ from the axis is proportional to: (where $a < r$)

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