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$\int_0^1 \frac{x}{(1-x)^{3/4}} dx = $

$\int_{\frac{\pi}{3}}^{\frac{\pi}{2}} \frac{\sqrt{1+\cos x}}{(1-\cos x)^{\frac{5}{2}}} d x=$

$\int_{-2}^2 |[x]| \, dx$ का मान ज्ञात कीजिए।

मान लीजिए $f:[0,1] \rightarrow [0,1]$ एक सतत फलन है ताकि सभी $x \in [0,1]$ के लिए $x^2+(f(x))^2 \leq 1$ और $\int_0^1 f(x) dx = \frac{\pi}{4}$ हो। तब,$\int_{\frac{1}{2}}^{\frac{1}{\sqrt{2}}} \frac{f(x)}{1-x^2} dx$ का मान ज्ञात कीजिए।

$\int_{-2}^4 \left|2-x^2\right| dx =$

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