R = {(pi, pi), (pi^2, pi^2), (pi^3, pi^3), (p | vedclass

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(B) Let the set be $A = \{\pi, \pi^2, \pi^3\}$.$1$. Reflexivity: For $R$ to be reflexive,$(a, a) \in R$ for all $a \in A$. Here,$(\pi, \pi) \in R$,$(\

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reflexive but not symmetric nor transitive

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(B) Let the set be $A = \{\pi, \pi^2, \pi^3\}$.$1$. Reflexivity: For $R$ to be reflexive,$(a, a) \in R$ for all $a \in A$. Here,$(\pi, \pi) \in R$,$(\pi^2, \pi^2) \in R$,and $(\pi^3, \pi^3) \in R$. Thus,$R$ is reflexive.$2$. Symmetry: For $R$ to be symmetric,if $(a, b) \in R$,then $(b, a) \in R$. We have $(\pi, \pi^2) \in R$,but $(\pi^2, \pi) 
otin R$. Thus,$R$ is not symmetric.$3$. Transitivity: For $R$ to be transitive,if $(a, b) \in R$ and $(b, c) \in R$,then $(a, c) \in R$. We have $(\pi, \pi^2) \in R$ and $(\pi^2, \pi^3) \in R$. For transitivity,$(\pi, \pi^3)$ must be in $R$. However,$(\pi, \pi^3) 
otin R$. Thus,$R$ is not transitive.Conclusion: $R$ is reflexive but neither symmetric nor transitive.

$R = \{(\pi, \pi), (\pi^2, \pi^2), (\pi^3, \pi^3), (\pi, \pi^2), (\pi^2, \pi^3)\}$ is defined on the set $A = \{\pi, \pi^2, \pi^3\}$. Then $R$ is . . . . . . .

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