left| {,begin{array}{*{20}{c}}{a - 1}&a&a | vedclass

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(d)$ \left| {\,\begin{array}{*{20}{c}}{a - 1}&a&{bc}\{b - 1}&b&{ca}\{c - 1}&c&{ab}\end{array}\,} ight| = \left| {\,\begin{

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इनमें से कोई नहीं

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(d)$ \left| {\,\begin{array}{*{20}{c}}{a - 1}&a&{bc}\{b - 1}&b&{ca}\{c - 1}&c&{ab}\end{array}\,} ight| = \left| {\,\begin{array}{*{20}{c}}a&a&{bc}\b&b&{ca}\c&c&{ab}\end{array}\,} ight| - \left| {\,\begin{array}{*{20}{c}}1&a&{bc}\1&b&{ca}\1&c&{ab}\end{array}\,} ight|$

= $ - \left| {\,\begin{array}{*{20}{c}}a&{{a^2}}&1\b&{{b^2}}&1\c&{{c^2}}&1\end{array}\,} ight| = - \left| {\,\begin{array}{*{20}{c}}a&{{a^2}}&1\{b - a}&{{b^2} - {a^2}}&0\{c - a}&{{c^2} - {a^2}}&0\end{array}\,} ight|$

                                               [${R_2} 	o {R_2} - {R_1};\,{R_3} 	o {R_3} - {R_1}$ द्वारा ]

= $ - (a - b)\,(b - c)\,(c - a)$.

$\left| {\,\begin{array}{*{20}{c}}{a - 1}&a&{bc}\\{b - 1}&b&{ca}\\{c - 1}&c&{ab}\end{array}\,} \right| = $

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