$1 + \frac{4^2}{3!} + \frac{4^4}{5!} + \dots \infty = $

  • A
    $\frac{e^4 + e^{-4}}{4}$
  • B
    $\frac{e^4 - e^{-4}}{4}$
  • C
    $\frac{e^4 + e^{-4}}{8}$
  • D
    $\frac{e^4 - e^{-4}}{8}$

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Similar Questions

श्रेणी $\frac{1}{2!} - \frac{1}{3!} + \frac{1}{4!} - \dots$ का योग है

$\frac{1}{1!} + \frac{4}{2!} + \frac{7}{3!} + \frac{10}{4!} + \dots \infty = $

$1 + \frac{1 + x}{2!} + \frac{1 + x + x^2}{3!} + \frac{1 + x + x^2 + x^3}{4!} + \dots \infty = $

$a>0, x \in R$ के लिए व्यंजक $\begin{aligned} & 1+x \log _e a+\frac{x^2}{2 !}\left(\log _e a\right)^2+\frac{x^3}{3 !}\left(\log _e a\right)^3+\ldots \end{aligned}$ किसके बराबर है?

$\frac{1}{2!} + \frac{1 + 2}{3!} + \frac{1 + 2 + 3}{4!} + \dots \infty = $

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