એક યાદચ્છિક ચલ X એ -1, 0, 1, 2 કિંમતો અનુક્રમ | vedclass

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Question

(D) બધી સંભાવનાઓ $0 \leq P(X=x_i) \leq 1$ હોવી જોઈએ.તેથી,$0 \leq \frac{1+3p}{4} \leq 1$,$0 \leq \frac{1-p}{4} \leq 1$,$0 \leq \frac{1+2p}{4} \leq 1$,અ

Vedclass · Accepted Answer

$-\frac{1}{16}$ અને $\frac{5}{4}$

Vedclass · Answer

(D) બધી સંભાવનાઓ $0 \leq P(X=x_i) \leq 1$ હોવી જોઈએ.તેથી,$0 \leq \frac{1+3p}{4} \leq 1$,$0 \leq \frac{1-p}{4} \leq 1$,$0 \leq \frac{1+2p}{4} \leq 1$,અને $0 \leq \frac{1-4p}{4} \leq 1$.આ અસમતાઓ ઉકેલતા:$1$) $1+3p \geq 0 \Rightarrow p \geq -1/3$$2$) $1-p \geq 0 \Rightarrow p \leq 1$$3$) $1+2p \geq 0 \Rightarrow p \geq -1/2$$4$) $1-4p \geq 0 \Rightarrow p \leq 1/4$આ બધાને ભેગા કરતા,$-\frac{1}{3} \leq p \leq \frac{1}{4}$ મળે છે.મધ્યક $E(X) = \sum x_i P(X=x_i) = (-1)\left(\frac{1+3p}{4}\right) + 0\left(\frac{1-p}{4}\right) + 1\left(\frac{1+2p}{4}\right) + 2\left(\frac{1-4p}{4}\right)$.$E(X) = \frac{-1-3p+1+2p+2-8p}{4} = \frac{2-9p}{4}$.આપેલ $-\frac{1}{3} \leq p \leq \frac{1}{4}$ માટે,$E(X)$ નો વિસ્તાર શોધીએ:જો $p = 1/4$,તો $E(X) = \frac{2-9(1/4)}{4} = \frac{2-2.25}{4} = -\frac{0.25}{4} = -\frac{1}{16}$.જો $p = -1/3$,તો $E(X) = \frac{2-9(-1/3)}{4} = \frac{2+3}{4} = \frac{5}{4}$.આમ,ન્યૂનતમ કિંમત $-\frac{1}{16}$ અને મહત્તમ કિંમત $\frac{5}{4}$ છે.

$X = x_i$	$0$	$1$	$2$	$3$	$4$
$P(X = x_i)$	$0.4$	$0.3$	$0.1$	$0.1$	$0.1$

$x$	$0$	$1$	$2$	$3$	$4$	$5$	$6$	$7$
$P(X=x)$	$0$	$k$	$2k$	$2k$	$3k$	$k^2$	$2k^2$	$7k^2+k$

$X=x$	$0$	$1$	$2$	$3$	$4$
$P(X=x)$	$0.4$	$0.3$	$0.1$	$0.1$	$0.1$

$x$	$-2$	$-1$	$3$	$4$	$6$
$P(X=x)$	$\frac{1}{5}$	$a$	$\frac{1}{3}$	$\frac{1}{5}$	$b$

$X$	$1$	$2$	$3$	$4$	$5$	$6$	$7$	$8$
$P(X=x)$	$0.15$	$0.23$	$0.12$	$0.10$	$0.20$	$0.08$	$0.07$	$0.05$

Similar Questions

યાદચ્છિક ચલ $X$ નું સંભાવના વિતરણ નીચે મુજબ આપેલ છે:
$X = x_i$ $0$ $1$ $2$ $3$ $4$
$P(X = x_i)$ $0.4$ $0.3$ $0.1$ $0.1$ $0.1$

તો $X$ નું વિચરણ શોધો.

એક યાદચ્છિક ચલ $X$ નું સંભાવના વિતરણ નીચે મુજબ છે:

$x$ $0$ $1$ $2$ $3$ $4$ $5$ $6$ $7$

$P(X=x)$ $0$ $k$ $2k$ $2k$ $3k$ $k^2$ $2k^2$ $7k^2+k$

$P(0 < X < 6)$ ની કિંમત શોધો.

યાદચ્છિક ચલ $X$ નું સંભાવના વિતરણ નીચે મુજબ આપેલ છે:
$X=x$ $0$ $1$ $2$ $3$ $4$
$P(X=x)$ $0.4$ $0.3$ $0.1$ $0.1$ $0.1$
$X$ નું વિચરણ શોધો.

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