{{sqrt {6 + 2sqrt 3 + 2sqrt 2 + 2sqrt 6 } - 1 | vedclass

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Question

(a) ${{\sqrt {6 + 2\sqrt 3 + 2\sqrt 2 + 2\sqrt 6 } - 1} \over {\sqrt {5 + 2\sqrt 6 } }}$

= ${{(1 + \sqrt 2 + \sqrt 3 ) - 1} \over {(\sqrt 3 + \sqrt

Vedclass · Accepted Answer

$1$

Vedclass · Answer

(a) ${{\sqrt {6 + 2\sqrt 3 + 2\sqrt 2 + 2\sqrt 6 } - 1} \over {\sqrt {5 + 2\sqrt 6 } }}$

= ${{(1 + \sqrt 2 + \sqrt 3 ) - 1} \over {(\sqrt 3 + \sqrt 2 )}}$= ${{\sqrt 3 + \sqrt 2 } \over {\sqrt 3 + \sqrt 2 }} = 1$.

${{\sqrt {6 + 2\sqrt 3 + 2\sqrt 2 + 2\sqrt 6 } - 1} \over {\sqrt {5 + 2\sqrt 6 } }}$

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