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(D) The flux through a surface depends on the solid angle subtended by the surface at the position of the charge.For a square of side $b$ with a charg

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If both $Assertion$ and $Reason$ are false.

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(D) The flux through a surface depends on the solid angle subtended by the surface at the position of the charge.For a square of side $b$ with a charge $q$ at height $d = h/4$ above its center,the solid angle $\Omega$ subtended by the square at the charge is given by $\Omega = 4 \arcsin \left( \frac{b^2}{b^2 + 4d^2} \right)$.The flux $\phi$ is given by $\phi = \frac{q \Omega}{4\pi \epsilon_0}$.Since the solid angle $\Omega$ depends on the ratio of the side length $b$ to the height $d$,the flux depends on the side length $b$. Thus,the $Assertion$ is false.Gauss's law states that the total flux through a closed surface is $q_{enclosed} / \epsilon_0$,which is independent of the shape or size of the Gaussian surface. Thus,the $Reason$ is true.Therefore,the correct option is $D$.

$Assertion (A):$ $A$ charge $q$ is placed at a height $h/4$ above the center of a square of side $b$. The flux associated with the square is independent of the side length $b$.
$Reason (R):$ Gauss's law is independent of the size of the Gaussian surface.

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$Assertion (A):$ $A$ charge $q$ is placed at a height $h/4$ above the center of a square of side $b$. The flux associated with the square is independent of the side length $b$.$Reason (R):$ Gauss's law is independent of the size of the Gaussian surface.