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(B) According to Molecular Orbital Theory,the bond order is calculated as $	ext{Bond Order} = \frac{N_b - N_a}{2}$.For a diatomic molecule with $15$

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$15$

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(B) According to Molecular Orbital Theory,the bond order is calculated as $	ext{Bond Order} = \frac{N_b - N_a}{2}$.For a diatomic molecule with $15$ electrons (like $NO$),the molecular orbital configuration is: $\sigma 1s^2, \sigma^* 1s^2, \sigma 2s^2, \sigma^* 2s^2, \sigma 2p_z^2, \pi 2p_x^2 = \pi 2p_y^2, \pi^* 2p_x^1$.Number of bonding electrons $(N_b)$ = $2+2+2+2+2 = 10$.Number of antibonding electrons $(N_a)$ = $2+2+1 = 5$.$	ext{Bond Order} = \frac{10 - 5}{2} = \frac{5}{2} = 2.5$.Thus,the total number of electrons in $AX$ is $15$.

$AX$ is a covalent diatomic molecule where $A$ and $X$ are second row elements of the periodic table. Based on Molecular Orbital Theory,the bond order of $AX$ is $2.5$. The total number of electrons in $AX$ is ........... (Round off to the nearest integer).

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