In the following the correct bond order sequence is :
In the following the correct bond order sequence is :
- [JEE MAIN 2021]
- A
$\mathrm{O}_{2}^{+}>\mathrm{O}_{2}>\mathrm{O}_{2}^{-}>\mathrm{O}_{2}^{2-}$
- B
$\mathrm{O}_{2}>\mathrm{O}_{2}^{-}>\mathrm{O}_{2}^{2-}>\mathrm{O}_{2}^{+}$
- C
$\mathrm{O}_{2}^{2-}>\mathrm{O}_{2}^{+}>\mathrm{O}_{2}^{-}>\mathrm{O}_{2}$
- D
$\mathrm{O}_{2}^{+}>\mathrm{O}_{2}^{-}>\mathrm{O}_{2}^{2-}>\mathrm{O}_{2}$
Similar Questions
Use molecular orbital theory to explain why the $Be_{2}$ molecule does not exist.
Use molecular orbital theory to explain why the $Be_{2}$ molecule does not exist.
Bond order of $C_2$ vapour is :
Bond order of $C_2$ vapour is :
Which of the following is paramagnetic
Which of the following is paramagnetic
What is the number of unpaired electron(s) in the highest occupied molecular orbital of the following species : $N _2: N _2^{+} ; O _2 ; O _2^{+}$?
What is the number of unpaired electron(s) in the highest occupied molecular orbital of the following species : $N _2: N _2^{+} ; O _2 ; O _2^{+}$?
- [JEE MAIN 2023]
According to Molecular Orbital Theory,
($A$) $\mathrm{C}_2^{2-}$ is expected to be diamagnetic
($B$) $\mathrm{O}_2{ }^{2+}$ is expected to have a longer bond length than $\mathrm{O}_2$
($C$) $\mathrm{N}_2^{+}$and $\mathrm{N}_2^{-}$have the same bond order
($D$) $\mathrm{He}_2^{+}$has the same energy as two isolated He atoms
According to Molecular Orbital Theory,
($A$) $\mathrm{C}_2^{2-}$ is expected to be diamagnetic
($B$) $\mathrm{O}_2{ }^{2+}$ is expected to have a longer bond length than $\mathrm{O}_2$
($C$) $\mathrm{N}_2^{+}$and $\mathrm{N}_2^{-}$have the same bond order
($D$) $\mathrm{He}_2^{+}$has the same energy as two isolated He atoms
- [IIT 2016]