Which of the following is paramagnetic?

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(D) $CN^{-}$,$CO$,and $NO^{+}$ are isoelectronic with $14$ electrons each,and there are no unpaired electrons in the Molecular Orbital $(MO)$ configur

Vedclass · Accepted Answer

$O_{2}^{-}$

Vedclass · Answer

(D) $CN^{-}$,$CO$,and $NO^{+}$ are isoelectronic with $14$ electrons each,and there are no unpaired electrons in the Molecular Orbital $(MO)$ configuration of these species.Therefore,these are diamagnetic.$O_{2}^{-}$ has $17$ electrons and is paramagnetic due to the presence of one unpaired electron in its antibonding $\pi^{*}$ orbital.$(CN^{-}, CO, NO^{+}) \; 14 \; e^{-} = \sigma 1s^{2}, \sigma^{*} 1s^{2}, \sigma 2s^{2}, \sigma^{*} 2s^{2}, \sigma 2p_{z}^{2}, \pi 2p_{x}^{2} \approx \pi 2p_{y}^{2}$ (No unpaired electron,diamagnetic).$O_{2}^{-} = \sigma 1s^{2}, \sigma^{*} 1s^{2}, \sigma 2s^{2}, \sigma^{*} 2s^{2}, \sigma 2p_{z}^{2}, \pi 2p_{x}^{2} \approx \pi 2p_{y}^{2}, \pi^{*} 2p_{x}^{2} \approx \pi^{*} 2p_{y}^{1}$ (One unpaired electron,paramagnetic).

Similar Questions

Which of the following statements are correct for the peroxide ion $(O_{2}^{2-})$?
$(i)$ It has a bond order of $1$.
$(ii)$ It is diamagnetic.
$(iii)$ It has four completely filled antibonding molecular orbitals.
$(iv)$ It is isoelectronic with neon.

Which of the following species has the highest bond order?

Provide the energy level diagram obtained by the overlapping of $2p_{z}$ orbitals and show the diagram of the resulting molecular orbitals.

What is the correct order of bond lengths in the following molecules? $I. O_2, II. O_2^+, III. O_2^-, IV. O_2^{2-}$

Vedclass Test Series

Exam Paper Generator

Online Exam Module