ldots ldots is one of the zeros of p(x) = x^{ | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(D) To find the zeros of the polynomial $p(x) = x^{3} + 7x^{2} + 11x + 5$,we test the given options by substituting them into the polynomial.If $x = -

Vedclass · Accepted Answer

$-1$

Vedclass · Answer

(D) To find the zeros of the polynomial $p(x) = x^{3} + 7x^{2} + 11x + 5$,we test the given options by substituting them into the polynomial.If $x = -1$:$p(-1) = (-1)^{3} + 7(-1)^{2} + 11(-1) + 5$$p(-1) = -1 + 7(1) - 11 + 5$$p(-1) = -1 + 7 - 11 + 5$$p(-1) = 12 - 12 = 0$Since $p(-1) = 0$,$x = -1$ is a zero of the polynomial $p(x)$.

$\ldots \ldots$ is one of the zeros of $p(x) = x^{3} + 7x^{2} + 11x + 5$.

Similar Questions

Classify the following as linear,quadratic,or cubic polynomial: $x^{3} + 5x^{2} + 12$.

Using the remainder theorem,find the remainder when the polynomial $p(x) = x^{3} + x^{2} - 26x + 24$ is divided by the divisor $x - 6$.

Without finding the cubes,factorise $(x-2 y)^{3}+(2 y-3 z)^{3}+(3 z-x)^{3}$.

Factorise $6x^{3}-23x^{2}+29x-12$.

Evaluate the following using suitable identities:
$(107)^{2}$

Vedclass Test Series

Exam Paper Generator

Online Exam Module