$A (3, 3)$ and $B (6, 1)$ are the given points. Find the point $C$ on the line $\overleftrightarrow{AB}$ such that $A-B-C$ and $3 AB = BC$.

  • A
    $(15, -5)$
  • B
    $(5, -3)$
  • C
    $(10, -5)$
  • D
    $(12, -1)$

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