The mid-point of the line segment joining the points $A(-2, 8)$ and $B(-6, -4)$ is

Find the area of a quadrilateral having the vertices $(-1, -1), (-4, -2), (-5, -4),$ and $(-2, -3)$.

The line segment joining $A(2, 2)$ and $B(2, -2)$ intersects $\ldots \ldots \ldots \ldots$

$(0, 0), (3.1, 0)$ and $(0, 4.5)$ are the vertices of $\ldots \ldots \ldots \ldots$ triangle.

If one of the end points of the diameter of a circle is $(0,0)$ and the centre of the circle is $(-2,4),$ then the other end point of the diameter is.........

$A (3, 3)$ and $B (6, 1)$ are the given points. Find the point $C$ on the line $\overleftrightarrow{AB}$ such that $A-B-C$ and $3 AB = BC$.