The point which lies on the perpendicular bis | vedclass

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(A) We know that the perpendicular bisector of any line segment passes through the midpoint of that line segment.The midpoint of the line segment join

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$(0,0)$

Vedclass · Answer

(A) We know that the perpendicular bisector of any line segment passes through the midpoint of that line segment.The midpoint of the line segment joining the points $A(-2, -5)$ and $B(2, 5)$ is calculated using the midpoint formula:Midpoint $= \left( \frac{x_1 + x_2}{2}, \frac{y_1 + y_2}{2} \right)$Substituting the given coordinates:Midpoint $= \left( \frac{-2 + 2}{2}, \frac{-5 + 5}{2} \right) = \left( \frac{0}{2}, \frac{0}{2} \right) = (0, 0)$Since the perpendicular bisector must pass through the midpoint of the segment,the point $(0, 0)$ lies on the perpendicular bisector.

The point which lies on the perpendicular bisector of the line segment joining the points $A (-2,-5)$ and $B (2,5)$ is

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