જો $\sec \theta = \frac{13}{5}$ હોય,તો $\cos \theta = \ldots \ldots \ldots \ldots$

  • A
    $\frac{12}{5}$
  • B
    $\frac{5}{12}$
  • C
    $\frac{5}{13}$
  • D
    $\frac{13}{12}$

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'True' (સાચું) અથવા 'False' (ખોટું) લખો અને તમારા જવાબનું સમર્થન કરો.
$(\tan \theta+2)(2 \tan \theta+1)=5 \tan \theta+\sec ^{2} \theta$

જો $a \sin \theta = 3$ અને $a \cos \theta = 4$ હોય,તો $a = \dots$ (જ્યાં $a > 0$).

જો $3 \cot \theta = 4$ હોય,તો $\frac{1 - \tan^2 \theta}{1 + \tan^2 \theta} = \dots$ શોધો.

$(1+\tan ^{2} \theta)(1-\sin \theta)(1+\sin \theta)$ નું સાદું રૂપ આપો.

$\tan (65^\circ - \theta) - \cot (25^\circ + \theta) - \sec (55^\circ - \theta) + \operatorname{cosec}(35^\circ + \theta) = \ldots \ldots \ldots \ldots$ (જ્યાં,$0 < \theta < 25^\circ$)

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