sqrt{2} is a polynomial of degree | vedclass

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Question

$\sqrt{2}$ is a constant polynomial. The only term here is $\sqrt{2}$ which can be written as $\sqrt{2} x^{0}.$

So, the exponent of $x$ is zero. Th

Vedclass · Accepted Answer

$0$

Vedclass · Answer

$\sqrt{2}$ is a constant polynomial. The only term here is $\sqrt{2}$ which can be written as $\sqrt{2} x^{0}.$

So, the exponent of $x$ is zero. Therefore, the degree of the polynomial is $0 .$

Hence, $(c)$ is the correct answer.

$\sqrt{2}$ is a polynomial of degree

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